Draw the intersection line between the beta plane and the first bisecting. Orthographic projection.

We traced a point any of the first bisecting.
For this, we draw a straight from the alpha plane, parallel to the ground line.
The first bisecting forms 45 degrees with the projection planes, so the dimensions and the distances of all its points, will be equal.
We apply the general procedure of intersection of planes, we note that the point of cut of the traces coincide. Therefore, we need a second common point to the two planes, to find their line of intersection.

We perform the intersection of the straight R, with the beta plane.
for this, along this line we draw a horizontal plane.
We found the intersection line of these two planes.

At the point of cut of this line of intersection s, with the straight R, we will obtain a point B, common to the three planes.
Uniting this point with the point of the traces v two and H one, draw the line of intersection searched.
procedure in the Diédrico system.
We point the alpha traces on the Earth line, which corresponds to the traces of the foreground bisector.
We apply the general procedure of intersection of planes, at the point of cut of the trace Alpha one with the trace beta one, we obtain the trace H one, of the line of intersection, and the point of cut of the vertical traces of the planes generates the trace v two.
These two traces match. Therefore, we need a second common point to the two planes, to find their line of intersection.

To do this, we draw a straight either from the bisector plane, and find its intersection point with the beta plane.
For any dimension, the vertical projection of a line contained in this bisector is drawn.
by axial symmetry, we carry with the same measure to draw the horizontal projection of this line.
We observe that the dimension and the distance of the projections of this line is the same, because in the first bisector all its points have the same dimension as distance.
Along this line we draw a horizontal plane.
that will generate a single vertical trace, Delta two.
found the intersection line of Delta and beta planes.

By having only one vertical trace, this intersection line will have its horizontal projection parallel to the beta one trace.
At the cutting point of the projection s one, with the projection R one, we will obtain B one, which is the horizontal projection of a common point to the three planes.
We draw your vertical projection over Delta two.
Unite B One with H one, to trace I one.
and Uniting B two with V two, we will draw the vertical projection of the searched intersection line.
The projections of this line, form the same angle with respect to the lines of land, being contained in the first bisecting.

In the first bisecting
Elevation = Distance