Find the Dihedral projections of the straight I, intersection of the alpha and beta planes.

Following the procedure of intersection between planes, we joined the vertical traces Alpha two with beta two, to find, at its intersection, the Trace v two.
And joining the horizontal traces of the planes, we find the trace H one of this line of intersection.
We observe that the two traces of this line, coincide in the same place.

The line will go through this point, but we need another point so we can draw it.

To do this, we use the auxiliary drawing method. That is to draw a plane, for example, a horizontal, by the dimension that we want. And with him, we found the intersections with the other two planes given. In the cut of the two auxiliary intersection lines, we will have a common point to the three planes. This point joins with the one already found, to form the line of intersection of the planes given Alpha and beta.

We draw a horizontal auxiliary plane, because of the dimension or height that we want.
then draw the intersection of the Delta Auxiliary plane with the alpha plane. The horizontal projection of this line will be parallel to the Alpha one trace. resulting in a straight edge, where the projection r two coincides with its trace v two.

Then we found the intersection of the Delta plane with the beta. Knowing, that the horizontal projection is parallel to the trace of the plane beta one. resulting in a horizontal line.

at the intersection of these two horizontal projections, R one and S one, we will find the projection to one, from the common point to the three planes.

We draw your vertical projection on the Delta two auxiliary plane.
Unite h One with a one, in order to draw the projection I one, of the line of intersection searched.
and join this same point with a two, to plot the projection I two, of this straight.
Knowing that the lines are infinite, we must draw also their hidden parts.